这个问题在这里已经有了答案:
mongodb group values by multiple fields
(3 个回答)
4年前关闭。
例如我有一个集合:
{ "_id" : 1, "name" : "abc", "score" : 10 }
{ "_id" : 2, "name" : "abc", "score" : 15 }
{ "_id" : 3, "name" : "abc", "score" : 20 }
{ "_id" : 4, "name" : "xyz", "score" : 10 }
{ "_id" : 5, "name" : "xyz", "score" : 15 }
{ "_id" : 6, "name" : "xyz", "score" : 20 }
如何在 Mongodb 中进行查询以按
name 分组然后按
score 排序和
limit=2 一起带走.我想变成这样:
{"_id": "abc", "items": [
{ "_id" : 3, "name" : "abc", "score" : 20 },
{ "_id" : 2, "name" : "abc", "score" : 15 }]
}
{"_id": "xyz", "items": [
{ "_id" : 6, "name" : "xyz", "score" : 20 },
{ "_id" : 5, "name" : "xyz", "score" : 15 }]
}
请您参考如下方法:
我的解决方案是
db.collection.aggregate([
{$sort:{name:-1, score:-1}},
{$group:{_id:"$name",items:{$push:{score:"$score"}}}},
{$project:{items:{$slice:["$items", 2]}}}])
.pretty()
返回
{
"_id" : "abc",
"items" : [
{
"score" : 20
},
{
"score" : 15
}
]
}
{
"_id" : "xyz",
"items" : [
{
"score" : 20
},
{
"score" : 15
}
]
}




